Question

please give fast answer of this question(given in attachment) please these is very important ​

Answer 1

Answer:

see below

Step-by-step explanation:

Let ABCD is a rhombus.

⇒  AB=BC=CD=DA                     [ Adjacent sides are eqaul in rhombus ]

In △AOD and △COD

⇒  OA=OC          [ Diagonals of rhombus bisect each other ]

⇒  OD=OD         [ Common side ]

⇒  AD=CD         

∴  △AOD≅△COD              [ By SSS congruence rule ]

⇒  ∠AOD=∠COD                [ CPCT ]

⇒  ∠AOD+∠COD=180o             [ Linear pair ]

⇒  2∠AOD=180o.

∴  ∠AOD=90o.

Hence, the diagonals of a rhombus bisect each other at right angle.