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given p(x) = x³-ax²+6x-a, g(x) =x - a
to find the remainder when p(x) is divided by x - a
put g(x) = x - a = 0
therefore x = a
substitute x = a in the given polynomial and equate it to zero
p(a) = a³-a*a²+6a-a = 0
=> a³-a³+5a = 0
=> 5a = 0
=> a = 0
remainder is zero
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