Question

Please give full explanation.
if |x-1| + |y-2| + (z-3)^2 ≤ 0 then find the value of x+y+z (where x, y, z € R)​

Answer 1

Answer:

6

Step-by-step explanation:

(x+y+z)^2 = x^2 + y^2 + z^2   +   2( xy + yx + zx)

Now,

(x+y+z)^2 = 18 + 2*9

               = 36

        Finally, x= 6

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