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answer: angle B=80,
angle A =40,
angle ACB=60 ,
angle ECB=100,
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Answer:
We know,
∠ACE + ∠ECD = 40 + 80 = 120
∴ ∠C = 180 - 120( Linear Pair)
∠C = 60
⇒ ∠B+ ∠A = 120 ( exterior angle of one side is equal to sum of other two interior angle)
In ΔABC,
∠A+∠B+∠C = 180 ( Angle sum Property)
If ∠A= ∠B
∵ 2∠A = 120
∴∠A= 60
∠B = 60
∠C = 60
⇒It is an Equilateral Triangle
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