please give hybrid structure of NiCl4
Answers
Answered by
1
the Hybrid structure Of NiCl4
NiCl42- = Ni2+ + 4Cl-
In NiCl42-, there is Ni2+ ion, However,
In presence of weak field Cl-ligands, NO pairing of d-electrons occurs. Therefore, Ni2+ undergoes sp3hybridization to make bonds with Cl-ligands in tetrahedral geometry. As there are unpaired electrons in the d-orbitals, NiCl42- is paramagnetic.
NiCl42- = Ni2+ + 4Cl-
In NiCl42-, there is Ni2+ ion, However,
In presence of weak field Cl-ligands, NO pairing of d-electrons occurs. Therefore, Ni2+ undergoes sp3hybridization to make bonds with Cl-ligands in tetrahedral geometry. As there are unpaired electrons in the d-orbitals, NiCl42- is paramagnetic.
Attachments:
Similar questions