Question

please give it's answer

Answer 1

I hope this is the correct answer

Answer 2

For my convenience, I am taking thetha as A, 

Given that,
2 Cos A = √3,
=> Cos A = ((√3)/2),

We know that, 
[tex] cos ^{2}A + sin ^{2}A = 1, =\ \textgreater \ Sin A = \sqrt{ 1 - Cos^{2} A} [/tex]

=> Sin A = √(1-3/4),
=> Sin A = √(1/4),
=> Sin A = 1/2,

We also know that, Sin 3A = 3 Sin A - 4 Sin³ A,

Now, We need to prove that, Sin 3A = 1,

Substituting what we got,
=> Sin 3A = 3(1/2) - 4(1/2)³,
=> Sin 3A = 3/2 -  4/8,
=> Sin 3A = 3/2 - 1/2,
=> Sin 3A = 1,

Therefore We proved it !, Hence we got the solution !,

Hope you understand, Have A Great Day ! Advance Merry Christmas !
Thanking you, Bunti 360 !