Question

please give me a answer .​

Answer 1

Answer:

given:- BD=AC, AE=EB & ✓ADB=✓ACB

1)∆ABD=∆BAC

in ∆abd and bac

bd=AC (given)

angle adb= angle acb (given)

ab=ab (common)

therefore ∆abd =∆bac

AD=BC by c.p.c.t. - - -(1)

2)∆aed=∆bec

in ∆aed and bec

AD=BC (from 1)

angle adb=angle acb (given)

ae=eb

therefore ∆ AED=∆BEC

hope it helps uuh