Question

please give me a answer

Answer 1

540 is the answer.....

Answer 2

Hi friend!
Let's see,

We can find two triangles over here who's base and height has been given.
∆BCD & ∆BAD
Their heights are CM and AL respectively.

Area of ∆BAD =
$\frac{bh}{2}$
$= \frac{36 \times 19}{2}$

Area of ∆BCD =
$\frac{bh}{2}$

$= \frac{36 \times 11}{2}$

Area of ABCD = A. of ∆BAD + A. of ∆BCD

$= \frac{(36 \times 19) + (36 \times 11)}{2} \\ \\ = \frac{36(19 + 11)}{2} \\ \\ = \frac{36 \times 30}{2} \\ \\ = \frac{1080}{2} \\ \\ = 540 {cm}^{2}$

Therefore, area of Quadrilateral ABCD = 540cm²

Hope you found my answer useful. Keep Smiling!