Question

please give me all answer then I will mark us brainlist

Answer 1

Hey user!

13.

x=1.2727.....

Let it be equation no.1

Multiply by 100

100x=127.2727..

Let it be equation no.2

Equation no.2-equation no.1

100x-x=(127.2727...)-(1.2727...)

99x=126

X=126/99=42/33

14.As we know;x^3+y^3+z^-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)

If (x+y+z)=0

x^3+y^3+z^3-3xyz=0*(x^2+y^2+z^2-xy-yz-zy)

=x^3+y^3+z^3-3xyz=0

=>x^3+y^3+z^3=3xyz

Thus proved.

15.i)

If f(x)is divided by g(x) the remainder is f(1/3)

=>f(1/3)=9*(1/3)^3-3*(1/3)^2+14*1/3-3

=9*1/27-3*1/9+14*1/3-3

=1/3-1/3+14/3-3

=1-1+14-9/3

=1+13-9/3

=14-9/3

=5/3

Hope this answer helped you....pls mark as brainliest