Question

please give me all answers it is very urgent​

Answer 1

Step-by-step explanation:

7.) x = 1-√2

1 = 1 × 1+√2

x 1-√2. 1+√2

= 1 + √2 = 1+ √2 = -1 -√2

1-2. -1

x - 1 = (1-√2) -(-1 + √2)

x

={ x - 1 } ² ={( 1 - √2) -( 1 -√2) }²

x

=( x - 1 )² = { 1-√2+ 1 +√2) = 2² = 4

x

Answer 2

Answer:

$7. \: x = 1 - \sqrt{2} \\ {(x - \frac{1}{x} )} = {1 - \sqrt{2} + \frac{1}{1 - \sqrt{2} }}\\ = 1- \sqrt{2} + \frac{1 + \sqrt{2} }{(1 - \sqrt{2} )(1 + \sqrt{2} )} \\ = 1 - \sqrt{2} + \frac{1 + \sqrt{2} }{1 - 2} \\ = 1 - \sqrt{2} - 1 - \sqrt{2} \\ = - 2 \sqrt{2} \\ so \: {{(x - \frac{1}{x} )} }^{2} = {( - 2 \sqrt{2} )}^{2} = 8$[/tex]

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$9. \:( ii) \: \: \frac{ {4}^{ \frac{1}{4} } }{ {4}^{ \frac{1}{3} } } \\ = \frac{ {2}^{ \frac{2}{4} } }{ {2}^{ \frac{2}{3} } } \\ = \frac{ {2}^{ \frac{1}{2} } }{ { 2 }^{ \frac{2}{3} } } \\ = {2}^{ \frac{1}{2} - \frac{2}{3} } \\ = {2}^{ \frac{3 - 4}{6} } \\ = {2}^{ \frac{ -1 }{6} }$

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answer of 6 and 8 is in the attachments.

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