Question

please give me all the equations related to electricity (class10)

Answer 1

V=IR 
R=rho L/R
F=kq1q2/r^2
V=kq/r
P=E/T=H/T
H=I^2RT=V^2T/R=VIT
P=I^2R=V^2/R=VI
Hope it helps...:)

Answer 2

Hey Friend !!!

Equations of Class 10 CBSE Physics Chapter 12 Electricity :

[1] Electric Current, 'I'

I = $\frac{Q}{t}$

'Q' is net charge, 't' is time taken by a net charge to flow across any cross section of a conductor.

SI Unit : 1 A = 1 C / 1 s

'A' represents Ampere, which is SI unit of current I

'C' represents Coulomb, which is SI unit of Charge Q

's' represent seconds, which is SI unit of time t

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[2] Potential Difference, 'V'

V = W / Q

'W' is Work Done. 'Q' is net charge

SI Unit : 1 V = J C^[-1}

'J' represents Joules, which is SI unit of Work Done

'C' represents Coulomb, which is SI unit of Charge Q

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[3] Ohm's Law 

R = V / I

'V' is Potential Difference across the conductor, 'Q' is net charge, 'R' is a constant which shows resistance of a conductor.

SI unit is ohm (Ω)

1 Ω = 1 V / 1 A


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[4] Resistance, Resistivity, Length and Area Relation

R = ρ × $\frac{l}{A}$

'R' is a constant which shows resistance of a conductor, 'ρ' is resistivity of the conductor, 'l' is length of metallic conductor, 'A' is area of crosection.


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[5] Resistance in series :

$R_{s} = R_{1} + R_{2} + R_{3} +.....R_{n}$


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[6] Resistance in Parallel :

[tex] \frac{1}{ R_{p} } = \frac{1}{ R_{1} } + \frac{1}{ R_{2} } + \frac{1}{ R_{3} } + ..... + \frac{1}{ R_{n} } [/tex]


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[7] Heating Effect of Electric Current : 

H = V×I×t 

H = $\frac{V^{2} t }{R}$

H = I² Rt

Here 'H' represents Heat energy produced, and it's SI Unit is Joules (J)

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[8] Power 'P'

P = $V \frac{Q}{t} = VI$

P = I²R

P = V² / R

SI Unit of Electric Power is watt [W]

1 W =1 volt × 1 ampere

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[9] Electrical Energy Comsumed :

Electrical Energy Comsumed = Power in Kilowatts × Time in hour

SI Unit is kWh

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Some others thing related to electricity :
1kWh = 1000 watt × 3600 second = 3.6 × $<strong>10^{6}</strong>$ Joule (J) 

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If two resistance $R_{1}$ and $R_{2}$ are parallel, the effective resistance are :

[tex] \frac{1}{ R_{p} } = \frac{1}{ R_{1} } + \frac{1}{ R_{2} } [/tex]

$= \frac{ R_{2} + R_{1} }{R_{1} * R_{2} }$

$R_{p} = \frac{R_{1} * R_{2}}{R_{1} + R_{2}}$

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W = VQ          [ From Potential Difference Formula ]

W = VIt           [ I = Q/t , ∴ Q = It ]

W = H              [ ∵ H = VIt ]  

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Hope it Helps