Question

Please give me an answer it is necessary. I don't get these

Answer 1

Let us first balance Hydrogen.

Their are 2 hydrogen in LHS whereas 3 in RHS.

To make the hydrogen even in RHS let us place 2 in place of c.

So, their will be 4 hyrogen in RHS.

To balance it we will place 2 in LHS before H₂O.

From this information we get b = 2 and c = 2.

Now there are 2 sodium in RHS and only 1 in LHS.

To balance it we will place 2 at place of a.

And at last as there are sufficient hydrogen atoms in RHS so d = 1.

$Equation:\\2Na+2H_2O---->2NaOH+1H_2$

Hence, a = 2

b = 2

c = 2

and

d = 1

Option B is correct.