Math, asked by aslam445366, 7 days ago

please give me anawer of this question​

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Answered by kv44489
4

Answer:

The radius (r) of the circular playground => diameter/2 = 21/2 = 10.5 m

Area of the circular playground

=> π [ π = 22/7 ]

=> 22/7 × 10.5 × 10.5 = 346.5

then, the cost of repairing the floor at the rate of 230/m².

=> 230 × 346.5 = 79,695

Circumference or perimeter of the circular playground

=> 2πr [ π = 22/7 ]

=> 2 × 22/7 × 10.5

=> 2 × 22 × 1.5

=> 66 m

then, cost of fencing the playground at the rate of 75/m

=> 66 × 75

=> 4950

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