Question

Please give me ans of all three parts....

Answer 1

$\huge\boxed{\texttt{\fcolorbox{purple}{yellow}{Heya !!!}}}$

PROBABILITY (EVENT)=NO. OF TIMES EVENT OCCURED DIVIDED BY TOTAL NO. TRIALS

ANSWER:-

(i)P (blood group A)=

$10 \div 40 = 1 \div 4$

(ii)P ( blood group O)=

$3 \div 40$

(iii)P ( blood group AB)=

$25\div 40 = 5 \div 8$

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Answer 2

Total Students=40

$\boxed{\mathbf{Probability=\frac{Favourable\: Outcomes}{Total\: Outcomes}}}$

(1)Person Having Blood Group A=10

Favourable Outcomes=10

Total Outcomes=40

$\boxed{\mathbf{Probability(A)=\frac{10}{40}}}$

$\boxed{\mathbf{Probability(A)=\frac{1}{4}}}$

(2)Person Having Blood Group O=3

Favourable Outcomes=3

Total Outcomes=40

$\boxed{\mathbf{Probability(O)=\frac{3}{40}}}$

(3)Person Having Blood Group AB=15

Not Having =40-15=25

$\boxed{\mathbf{Probability(Not\:AB)=\frac{25}{40}}}$

$\boxed{\mathbf{Probability(Not\:AB)=\frac{5}{8}}}$