Question

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Answer 1

Answer:

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Given:-

• Length of Rectangle(l) = 40cm

• Breadth of Rectangle (b) = 22cm

To find :-

• Side of Square = ?

Solution :-

• Length of wire(L) = Perimeter of Rectangle

==> Perimeter of Rectangle = 2(l + b) = 2(40 + 22)

==> 2 × 62 = 124cm

Hence,

• Length of Wire (L) = 124 cm

Now,

• Side of square = x

Length of wire(L) = Perimeter of Square

• Perimeter of Square = 4x

• Perimeter of Square = 4x = 124

• ==> 4x = 124 ==> x = 124/4 = 31 cm

Now,

2nd part of Qus:-

To find:-

==> Area of Rectangle = l × b = 40 × 22 = 880cm^2

==> Area of Square = x × x = 31 × 31 = 961 cm^2

Hence,

• Square encloses more area than rectangle.

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Answer 2

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Given:-

Length of Rectangle(l) = 40cm

Breadth of Rectangle (b) = 22cm

To find :-

Side of Square = ?

Solution :-

Length of wire(L) = Perimeter of Rectangle

⇒ Perimeter of Rectangle = 2(l + b) = 2(40 + 22)

⇒ 2 × 62 = 124cm

Hence,

Length of Wire (L) = 124 cm

Now,

Side of square = x

Length of wire(L) = Perimeter of Square

Perimeter of Square = 4x

Perimeter of Square = 4x = 124

⇒4x = 124

⇒x = 124/4 = 31 cm

Now,

2nd part of Qus:-

To find:-

⇒ Area of Rectangle = l × b = 40 × 22 = 880cm^2

⇒ Area of Square = x × x = 31 × 31 = 961 cm^2