Question

please give me answer​

Answer 1

Answer:

At t = 0, initial velocity = u = OA  

At t = t, final velocity = v = OC

The distance S travelled in time t = area of the trapezium OABD

s = (1/2) x (OA + DB) × OD

s = (1/2) x (u + v) × t  

Since v = u + at,

s = (1/2) x (u + u + at) × t

s = ut + (1/2) at2  

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Answer 2

Answer:

The 2nd equation is s=ut + 1/2 at^2

Explanation:

Distance travelled = area of OABC

= area of rectangle + area of triangle

= length × breadth+ 1/2 × base×height

= OC × OA + 1/2 × AD× BD

= t×u + 1/2 × t×at

= ut+ 1/2 at^2

S = ut + 1/2 at^2