Math, asked by kumarsonu2, 9 months ago

please give me answer​

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Answered by dineshkumaryadav55
0

Step-by-step explanation:

1 :-

16x^2 - 81y^2 =

(4x)^2 - (9y) ^2

(4x+9y) (4x - 9y)

2 :-

4x^2y^2 - 25y^2 =

(2xy)^2 - (5y)^2 =

(2xy + 5y) (2xy - 5y)

3:-

x^4 - 16 =

(x^2)^2 - 4^2

= (x^2 + 4) (x^2 - 4)

4:-

9x^2 + 24x + 16

= 9x^2 + 12x + 12x + 16

= 3x (3x + 4) +4 (3x + 4)

= (3x+4) (3x+4)

= (3x+4)^2

5:-

4x^2y^2 - 4xyz + z^2 =

4x^2y^2 -2xyz -2xyz + z^2

= 2xy ( 2xy - z ) -z (2xy - z)

= (2xy-z) (2xy-z)

= (2xy-z)^2

6:-

x^2 / 36 - 49 =

(x/6)^2 - 7^2

(x/6 + 7) (x/6 - 7)

Answered by Anonymous
9

Answer:

Step-by-step explanation:

1 :-

16x^2 - 81y^2 =

(4x)^2 - (9y) ^2

(4x+9y) (4x - 9y)

2 :-

4x^2y^2 - 25y^2 =

(2xy)^2 - (5y)^2 =

(2xy + 5y) (2xy - 5y)

3:-

x^4 - 16 =

(x^2)^2 - 4^2

= (x^2 + 4) (x^2 - 4)

4:-

9x^2 + 24x + 16

= 9x^2 + 12x + 12x + 16

= 3x (3x + 4) +4 (3x + 4)

= (3x+4) (3x+4)

= (3x+4)^2

5:-

4x^2y^2 - 4xyz + z^2 =

4x^2y^2 -2xyz -2xyz + z^2

= 2xy ( 2xy - z ) -z (2xy - z)

= (2xy-z) (2xy-z)

= (2xy-z)^2

6:-

x^2 / 36 - 49 =

(x/6)^2 - 7^2

(x/6 + 7) (x/6 - 7)

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