please give me answer
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Answered by
0
Answer:
ATQ
t-3=0
t=3
putting the Value t=3 we get
=(3)^2-2×(3)^2+3×3
=9-18+9
=18-18
=0
(proved)
Answered by
1
Answer:
ATQ
t-3=0
t=3
putting the value t=3 get
(3)^2-2×(3)^2+3×3
9-18+9
18-18
o
Hence,proved
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