Math, asked by kumarsonu2, 8 months ago

please give me answer​

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Answered by pandasb09
0

Answer:

ATQ

t-3=0

t=3

putting the Value t=3 we get

=(3)^2-2×(3)^2+3×3

=9-18+9

=18-18

=0

(proved)

Answered by ravik666326
1

Answer:

ATQ

t-3=0

t=3

putting the value t=3 get

(3)^2-2×(3)^2+3×3

9-18+9

18-18

o

Hence,proved

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