Question

please give me answer​

Answer 1

Step-by-step explanation:

i hope this will help you.

Answer 2

Solution

Given That :-

• tan A = n/(n+1)
• tan B = 1/(2n+1)

Find :-

• Value of tan ( A + B)

Explanation

Using Formula

☛ tan(A + B) = (tan A + tan B )/(1 - tan A tan B)

So, now keep all above values

➥ tan ( A + B ) = [n/(n+1) + 1/(2n+1)]/[(1 - n/(n+1) * 1/(2n+1) ]

➥ tan ( A + B ) = [n*(2n+1)+(n+1)]/[(n+1)(2n+1)] × [(n+1)(2n+1)/(n+1)(2n+1)-n]

cancel (n+1)(2n+1) , by denominator & Numerator

➥ tan ( A + B ) = (2n² + n + n +1) × 1/(2n²+n+2n+1-n)

➥ tan ( A + B ) = (2n²+2n+1)/(2n²+2n+1)

Cancel denominator & Numerator

we got ,

➥ tan ( A + B ) = 1

Hence

• Value of tan (A + B) will be = 1

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