Question

please give me answer​

Answer 1

${\large{\boxed{\sf{a²+\frac{1}{a²}=23}}}}$

${\large{\boxed{\red{\sf{a²+b²=(a+b)²-2ab}}}}}$

$\large{→}$ ${\large{\boxed{\sf{a²+\frac{1}{a²}=(a+\frac{1}{a})²-2(a)(\frac{1}{a})}}}}$

$\large{→}$ ${\large{\boxed{\sf{23=(a+\frac{1}{a})²-2(1)}}}}$

$\large{→}$ ${\large{\boxed{\sf{(a+\frac{1}{a})²=23+2}}}}$

$\large{→}$ ${\large{\boxed{\sf{a+\frac{1}{a}=\sqrt{25}}}}}$

$\large{→}$ ${\large{\boxed{\green{\sf{a+\frac{1}{a}=5}}}}}$

${\large{\bold{\orange{\sf{Kindly\: vote \:me❤}}}}}$

${\large{\boxed{\green{\sf{Sai\:Charan\: |\: Shikshak\:of \:the\:year}}}}}$

Answer 2

Answer:

a+1/a = 5

Step-by-step explanation:

Given a²+1/a²=23

we know that by formula,

(a + b)² = a² + b² + 2 × a × b

Bring a² + 1/a² in the above format, hence the equation becomes,

(a + 1/a)² = a² + (1/a)² + 2 ×a² × 1/a²

(a + 1/a)² = 23 + 2 [ a² + 1/a² = 23 ]

Hence (a + 1/a)² = 25

Now by taking squre root both sides the equation becomes ,

a + 1/a = 5