Question

please give me answer​

Answer 1

Answer:

$\frac{1}{16}a^{2} + \frac{1}{4} b^{2} + 1 -\frac{1}{4} ab - b + \frac{1}{2}a$

Step-by-step explanation:

$(\frac{1}{4}a - \frac{1}{2} b+ 1)^{2} \\\\(\frac{1}{4}a)^{2} + (\frac{1}{2}b)^{2} + (1)^{2} +2((\frac{1}{4}a)( -\frac{1}{2}b) + (-\frac{1}{2}b)(1) + (\frac{1}{4}a)(1))\\\\\\\frac{1}{16}a^{2} + \frac{1}{4} b^{2} + 1 +2(-\frac{1}{8} ab - \frac{1}{2}b + \frac{1}{4}a) \\\\\frac{1}{16}a^{2} + \frac{1}{4} b^{2} + 1 -\frac{1}{4} ab - b + \frac{1}{2}a ( Ans)$