Question

please give me answer ​

Answer 1

What is your question first

Answer 2

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$k {x}^{2} + 6x + 1 = 0 \\ \\ a {x}^{2} + bx + c = 0 \\ \\ a = k \: \: \: b = 6 \: \: c = 1 \\ \\ {b}^{2} - 4ac = 0 \\ \\ {6}^{2} - 4k = 0 \\ \\ 4k = 36 \\ \\ k = \frac{36}{4} \\ \\ k = 9$

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