Math, asked by jhu1, 1 year ago

please give me answer

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Answered by rakeshmohata
0

x(3 -  \frac{2}{x} ) =  \frac{3}{x}  \\ or. \: 3x - 2  -  \frac{3}{x}  = 0 \\ or. \: 3x -  \frac{3}{x}  = 2 \\ or. \: 3(x -  \frac{1}{x} ) = 2 \\ or . \: x -  \frac{1}{x}  =  \frac{2}{3}  \\ or. \: (x -  \frac{1}{x} ) ^{3}  =  ({ \frac{2}{3} })^{3} .....cubing \: both \: sides \\ or. \:  {x}^{3}  -  { (\frac{1}{x} )}^{3}  - 3x \times \frac{1}{x}  \times (x -  \frac{1}{x} ) = \frac{8}{27}   \\ or. \:  {x}^{3}  -  ({ \frac{1}{x} })^{3}  = 3 \times  \frac{2}{3}  +  \frac{8}{27}  =  \frac{62}{27} ...ans
Hope ur required answer is 62/27.
Answered by Utsab11
0
answer of this question is 2
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