Question

please give me answer

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(3^0+8)÷(9)²​

Answer 1

:⟼  $({3}^{0} + 8) \div ( {9})^{2}$

:⟼  $(1 + 8) \div (9 \times 9)$

:⟼  $9 \div 81$

:⟼  $\frac{1}{9}$

:⟼  $\boxed{ 0.111 }$

Note:

Any number to the power $0$ is always $1$.

Answer 2

Answer:

$\frac{1}{9} = 0.11$

Step-by-step explanation:

Given :

$\large{ \frac{3^0 + 8}{9^2}}$

To find :

The value of the given number

Concept :

Any number power 0 is 1 => a⁰ = a

Solution :

$=> \large{ \frac{3^0 + 8}{9^2}} \\\\=> \large{ \frac{1 + 8}{9^2}} \\\\=> \large{ \frac{9}{9^2}}\\\\=> \frac{1}{9} = 0.\dot{1} = 0.11$

$\therefore \ \ \boxed {\large{ \frac{3^0 + 8}{9^2} = 0.11}}$

❖ Extra information :

⟡ Why any number power 0 = 1 ?

=> we know that xᵃ/xᵇ = xᵃ⁻ᵇ (if a>b)

So, if a = b, then all the x's in the numerator and denominator cut out to get 1 and xᵃ⁻ᵃ = x⁰

So, x⁰ = 1

Hope it helps!