Question

please give me answer

Answer 1

Given Equation is 2(y + 1)^2 + 5(y + 1) = 72

= > 2(y^2 + 1 + 2y) + 5y + 5 = 72

= > 2y^2 + 2 + 4y + 5y + 5 = 72

= > 2y^2 + 9y + 7 = 72

= > 2y^2 + 9y + 7 - 72 = 0

= > 2y^2 + 9y - 65 = 0

It is in the form of ax^2 + bx + c = 0, we get

a = 2, b = 9, c = -65.

The solutions are:

(1)

$x = \frac{-b + \sqrt{b^2 - 4ac} }{2a}$

$= \ \textgreater \ \frac{-(-9) + \sqrt{9^2 - 4 * 2 * (-65)} }{2 * 2}$

$= \ \textgreater \ \frac{-9 + \sqrt{81 + 520} }{4}$

$= \ \textgreater \ \frac{-9 + \sqrt{601} }{4}$


(2)

$x = \frac{-b- \sqrt{b^2 - 4ac} }{2a}$

$= \ \textgreater \ \frac{-9 - \sqrt{9^2 - 4 * 2 * (-65)} }{2 * 2}$

$= \ \textgreater \ \frac{-9- \sqrt{9^2 + 2 * 4 * 65} }{4}$

$= \ \textgreater \ \frac{-9 - \sqrt{81 + 520}} {4}$

$= \ \textgreater \ \frac{-9- \sqrt{601} }{4}$


Therefore the roots are: $x = \frac{- 9 + \sqrt{601} }{4} , \frac{-9- \sqrt{601} }{4}$


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks