Question

Please give me answer ​

Answer 1

Answer:

$6x {}^{2} - 12x \\ 3x(2x - 4x) = 0$

$2x - 4x = - 3 \\ - 2x = - 3 \\ x = \frac{3}{2}$

Step-by-step explanation:

ok

Answer 2

⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀☆ GIVEN POLYNOMIAL : 6x² - 12x = 0

$\qquad \dashrightarrow \sf 6x^2 - 12x = 0 \:\:$

$\qquad \dashrightarrow \sf 6x(x - 2 ) = 0 \:\:$

$\qquad \dashrightarrow \sf x = \: 0 \:\:or\:\: x = \:\: 2 \:\:$

$\qquad \therefore \pmb{\underline{\purple{\:x = 0 \:\:or\:\: x = \:\: 2 \:\: \:\: }} }\:\:\bigstar$

$\therefore \underline {\sf Hence, \:The :zeroes \:of\:Polynomial \:are \:\bf 0 \:\:or \:\: 2 \:\:}$

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⠀⠀⠀⠀⠀$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\qquad \qquad \boxed {\begin{array}{cc} \bf{\underline {\bigstar\:\: For \: a \:Quadratic \:Polynomial \::}}\\\\ \sf{ Whose \:\:zeroes \:\:are\:\:\alpha \:\&\;\: \beta\:\:} \\\\ 1)\:\: \alpha + \beta \: =\:\dfrac{-b}{a} \quad \bigg\lgroup \bf Sum\:of\;Zeroes \bigg\rgroup \\\\ 2)\:\: \alpha \times \beta \: =\:\dfrac{c}{a} \quad \bigg\lgroup \bf Product \:of\;Zeroes \bigg\rgroup \\\\ \end{array}}$

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