Question

Please give me answer ​

Answer 1

Solution :-

given that, the product of the zeroes of polynomial ax² - 6x - 6 is 4 .

we know that, the product of zeroes of equation ax² + bx + c is (c/a) .

so, comparing ax² - 6x - 6 with ax² + bx + c , we get,

• a = a
• b = (-6)
• c = (-6)

then,

→ Product of zeroes = c/a = 4

→ (-6)/a = 4

→ a = (-6/4)

→ a = (-3/2) (Ans.)

Learn more :-

JEE mains Question :-

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. Find all the zeroes of the polynomial x4

– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.

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