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a) In Pressure = Force/area,
as area is in denominator, the pressure will definitely become less if area is increased,
it is asked that if area is doubled and thrust remains the same.....suppose we have,
Force=4N Area=2m^2
Pressure=4/2=2 Pascals
if area is doubled=2×2=4m^2
thrust=4
pressure=4/4=1 Pascal
HENCE IF AREA IS DOUBLED, THE PRESSURE WILL BE HALVED.....
b) The thrust is in the numerator, if numerator is increased the quotient (pressure)will also increase...
SUPPOSE FORCE=4N, AREA = 2m^2
pressure=4/2= 2 pascals
IF THRUST IS DOUBLED=4×2=8N
AREA=2m^2
Pressure = 8/2= 4 pascals
Hence if thrust is double, the pressure will alap be doubled.....
hope it helps:)
plz mark as brainliest if you liked my explanation....
as area is in denominator, the pressure will definitely become less if area is increased,
it is asked that if area is doubled and thrust remains the same.....suppose we have,
Force=4N Area=2m^2
Pressure=4/2=2 Pascals
if area is doubled=2×2=4m^2
thrust=4
pressure=4/4=1 Pascal
HENCE IF AREA IS DOUBLED, THE PRESSURE WILL BE HALVED.....
b) The thrust is in the numerator, if numerator is increased the quotient (pressure)will also increase...
SUPPOSE FORCE=4N, AREA = 2m^2
pressure=4/2= 2 pascals
IF THRUST IS DOUBLED=4×2=8N
AREA=2m^2
Pressure = 8/2= 4 pascals
Hence if thrust is double, the pressure will alap be doubled.....
hope it helps:)
plz mark as brainliest if you liked my explanation....
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