Question

please give me answer.​

Answer 1

Step-by-step explanation:

cot X =√3

we know , cot π/6=√3

cot (π-π/6=-cot π/6=-√3 & cot ( 2π - π/6)=-cot=-√3

cot 5π/6=-√3 & cot 11π/6=-√3

x=5π{/6= 11π/6

cot x = cot 5π/6

tan x = tan 5π/6

x= nπ + 5π/6

x= nπ + 5π/6, n€z