Question

please give me answer

Answer 1

a, c,e are right
b, d are wrong

Answer 2

Answer :

a. 2x + 3 = 9 ( x = 3 )

=> Put x = 3 in the equation, we get

=> 2(3) + 3 = 9

=> 6 + 3 = 9

=> 9 = 9

L.H.S = R.H.S
Therefore x = 3 is the solution of the given equation.

$b. \: \: \frac{x}{3} = 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (x = 5) \\ \\ put \: x = 5 \: in \: the \: equation \: we \: get \\ \\ \frac{5}{5} = 5 \\ \\ 1 \: is \: not \: equals \: to \: 5 \\ \\ therefore \: l.h.s \: is \: not \: equals \: to \: r.h.s \\ so \: x = 5 \: is \: not \: a \: solution \: of \: the \: given \: equation$

c. 4x - 7 = 3x + 8 ( x = 15 )

Put x = 15 in the equation.

4(15) - 7 = 3(15) + 8

60 - 7 = 45 + 8

53 = 53

L.H.S = R.H.S
Therefore x = 15 is the solution of the given equation.

d. 2( x + 10 ) = 3( x - 2 ) ( x = 5 )

Put x = 5 in the equation, we get

2( 5 + 10 ) = 3( 5 - 2 )

2 × 15 = 3 × 3

30 is not equals to 9

L.H.S is not equals to R.H.S
Therefore x = 5 is not a solution of the given equation.

$e. \: \: \frac{x}{2} + \frac{x}{6} - 4 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: (x = 6) \\ \\ put \: x \: = 6 \: in \: the \: equation \: we \: get \\ \\ \frac{6}{2} + \frac{6}{6} = 0 \\ \\ 3 + 1 = 0 \\ \\ 4 \: is \: not \: equals \: to \: 0 \\ \\ l.h.s \: is \: not \: equals \: to \: r.h.s \: \\ therefore \: x = 6 \: is \: not \: a \: solution \: of \: given \: equation$

Hope it would help you