Question

please give me answer

Answer 1

Hey here is your answer,
In Triangle BOC,
BO=OC [Since, O is center, so both are equal to radius]
AND, Since BO=CO,
THEREFORE,
angle BCO= angle CBO=70°
SO, Angle BOC=180°-(70°+70°)
Angle BOC=40°
now, angle BOC=40°
SO, Angle AOC= 180°-40°=140°
THUS, In Triangle AOC,we have,
Angle AOC=140° and AO=OC (RADIUS)
therefore,
angle CAO= angle ACO=x
so, IN TRIANGLE AOC,
140+(x+x)=180°
2x=40°
x=20°
HENCE,
X=20° i.e. 3rd option