Question

please give me answer

Answer 1

what do you mean answered was answered always

Answer 2

solution

we can say that 1/cos theta= sec theta

so according to the question

L.H.S.----->>>>>

according to (a+b)^2

(tan theta + sec theta)^2 + (tan theta - sec theta)^2= tan^2 theta + sec^2 theta +2 tan theta * sec theta + tan^2 theta+ sec^2 theta-2tan theta * sec theta

now you cut the +2 tan theta *sec theta -2 tan theta *sec theta

then you observe

2 tan^2 theta+2 sec^2 theta

=> 2(tan^2 theta+ sec^2)

=> 2(sin^2 theta upon cos^2 theta+ 1 upon cos^2 theta)

=> 2(sin^2 theta+1 upon cos^2 theta)

by using cos^2 theta = 1-sin^2 theta

=> 2(1+sin^2 theta upon 1-sin^2 theta)

= R.H.S

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