Question

please give me answer​

Answer 1

this is your first part answer

Answer 2

(i). angle b= 50° (vertically opposite angles)

In triangle (i). sum of all angles=180°

So, 60° + angleB + angleA=180°

60° +50° + angleA =180°

angleA = 180°-110°

angleA = 70°

(ii). In fig (ii),

angleA +80° = 180° ( linear pair)

angleA = 180-80°= 100°

angleA + angleB + 35°=180°

100°+ angleB + 35°=180

angleB= 180-135= 45°