Question

please give me answer​

Answer 1

and the answer is three if I'm not wrong... hope it helps

Answer 2

Answer:

Step-by-step explanation:

Cos^2 20+ cos^2 70)+cot25/tan65+cot5cot10cot60cot80cot85

We have identity

Cos(90-a)=sin a tan(90-a)= cota ={Cos^2(90-20)+cos^2 70}+{cot(90-65)/tan 65)}+cot(90-85)cot(90-80)cot60 cot80 cot85}

=(Sin^2 70+cos^2 70) + tan 65/tan65+ (tan85 tan. 80 cot60 cot 80 cot85)

=1+1+ 1×√3×1 = 2+√3