Question

please give me answer ​

Answer 1

ac^2+cb^2=ab^2

(4)^2+(4)^2=ab^2

16+16=ab^2

32=ab^2

ab=+-√32
ab=+-√2^3
ab= 2 √2

Answer 2

Given AC=4cm

and isoceles triangle

so CB = 4cm

then by applying Pythagoras theorum

H^2=P^2+B^2

AB^2=4^2+4^2

AB^2=16+16

AB=√32

AB=4√2 cm or 5.65 approx

hope this helps you