Physics, asked by Aghaoprasad, 4 months ago

please give me answer as soon as possible​

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Answered by 2003sneha
1

Answer:

It can achieve escape at any speed, given sufficient propellant to provide new acceleration to the rocket to counter gravity's deceleration and thus maintain its speed. The escape velocity from Earth's surface is about 11,186 m/s (6.951 mi/s; 40,270 km/h; 36,700 ft/s; 25,020 mph; 21,744 kn).

Answered by akhilvinayak03
0

Answer:

11.2 km/s

Explanation:

The minimum velocity required for a body to escape earth's gravitational field is called the escape velocity. For earth, this has a constant value of 11.2 km/s.

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