Question

please give me answer bro​

Answer 1

Answer:

the part one answer is -24

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• x = 2, y = 3, z = (-4)

To find:

• Values of the given expressions

Solution:

$</p><p>(1) \:x^2y + y^2z \\ \implies (2)^2*(3) + (3)^2*(-4) \\ \implies 4*3 + 9*(-4) \\ \implies 12 - 36 \\ \implies \bold{-24} \\ \\</p><p>(2) -3x^2 - 4y^2 + 6z^2 \\ \implies -3*(2)^2 - 4*(3)^2 + 6*(-4)^2 \\ \implies -3*4 - 4*9 + 6*16 \\ \implies -12 - 36 + 96 \\ \implies \bold{48} \\ \\</p><p>(3)\:x^2yz - 3xy^2z \\ \implies (2)^2*(3)*(-4) - 3*(2)*(3)^2*(-4) \\ \implies 4*3*(-4) - 3*2*9*(-4) \\ \implies -48 + 216 \\ \implies \bold{168} \\ \\</p><p>(4)\:2xy + yz + 3x \\ \implies 2*(2)*(3) + (3)*(-4) + 3*(2) \\ \implies 12 - 12 + 6 \\ \implies \bold{6} \\ \\</p><p>(5)\:3xyz + y^2 \\ \implies 3*(2)*(3)*(-4) + (3)^2 \\ \implies -72 + 9 \\ \implies \bold{-63} \\ \\</p><p>(6)\: x^2 + 4xyz + y^2 + z^2 \\ \implies (2)^2 + 4*(2)*(3)*(-4) + (3)^2 + (-4)^2 \\ \implies 4 - 96 + 9 + 16 \\ \implies \bold{67}$

HOPE IT HELPS!!