Question

please give me answer fast 2​

Answer 1

Answer:

Step-by-step explanation:

$\tt{\bold{\bullet\,\,Area\,\,of\,\,the\,\,remaining\,\,portion=\,Ar(\square\,ABCD)\,-\,Ar(semicircle(BCB))}}$

$\sf{=length\times\,breadth-\dfrac{1}{2}\pi(radius)^2}$

$\sf{=40\times\,28-\dfrac{1}{2}\pi\cdot(14)^2}$

$\sf{=1120-\dfrac{1}{2}\times\dfrac{22}{7}\times14\times14}$

$\sf{=1120-22\times14}$

$\sf{=1120-308}$

$\sf{=812\,\,cm^2}$

Answer 2

Answer:

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