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Here's ur answer hope this helps u.
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RakshithaLokesh:
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sin=p/h
√3/2=p=√3 h=2
(2)^2=(√3)^2+b^2
4-3=√1=b
b=1
2(1/√3)^2-1
2/3-1
2-3/3
-1/3
√3/2=p=√3 h=2
(2)^2=(√3)^2+b^2
4-3=√1=b
b=1
2(1/√3)^2-1
2/3-1
2-3/3
-1/3
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