Question

please give me answer fast​

Answer 1

Let, a be the side of square, l be the length and b be the breadth of rectangle.

A/q, a = b

$\frac{ {a}^{2} }{lb} = \frac{ {a}^{2} }{al} = \frac{a}{l} = \frac{2}{3} \\ \\ l = \frac{3}{2} a$

Now,

$Perimeter \:of \:square = 4a$

and,

$Perimeter \: of \: Rectangle \\ = 2(l + b) \\ = 2( \frac{3}{2} a + a) \\ \: \: \: \: = 2( \frac{3a + 2a}{2} ) = 5a$

$∴ Required \: Ratio = \frac{4a}{5a} = 4:5$

Hope It Helps :)))

Answer 2

$\huge\pink{⛄ Answer ⛄}$

Option 1 : - 4 : 5

Hope it will help you✧◝(⁰▿⁰)◜✧

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