please give me answer fast please
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5x−2(2x−7) = 2(3x−1)+
⇒ 5x−4x+14 = 6x−2+
⇒ x+14 = 6x+
⇒ x−6x = −14
⇒ −5x =
⇒x=
and for verifying, put the value of x in LHS & RHS. if LHS=RHS then it's correct.
Hope this helps...
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Answered by
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Answer:
5x−2(2x−7) = 2(3x−1)+\frac{7}{2}
2
7
⇒ 5x−4x+14 = 6x−2+ \frac{7}{2}
2
7
⇒ x+14 = 6x+ \frac{3}{2}
2
3
⇒ x−6x = \frac{3}{2}
2
3
−14
⇒ −5x = \frac{-25}{2}
2
−25
⇒x= \frac{5}{2}
2
5
and for verifying, put the value of x in LHS & RHS. if LHS=RHS then it's correct.
Hope this helps...
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