Question

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Answer 1

Answer:

Step-by-step explanation:

As shown in the figure O is a point in exterior of Δ ABC

Let us join OA,OB and OC

As per rule :

sum of two sides of a triangle is greater than third side

Thus

$In \ the \ \triangle OAB\\\\OA + OB > AB----------------------(1)\\\\Similarly \ in \ the\ \triangle OAC\\\\OA+OC > AC-----------------------(2)\\\\Also\ in \ the\ \triangle OBC \\\\OB+OC > BC----------------------(3)\\\\Adding \ (1) \ , (2) \ and \ (3) \ we \ get\\\\OA+OB+OA+OC+OB+OC > AB+AC+BC\\\\2( OA+OB+OC) > AB + BC +CA\\\\OA+OB+OC >\frac12 ( AB +BC +CA)\\\\Hence \ Proved$

Answer 2

Answer:

please tell me this

answer bataoge to 50 thanks milaga

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