Question

please give me answer for 100 point

Answer 1

Answer:

Let draw a line PQ which is perpendicular to AB.

Since AB is parallel to EF.

So, PQ is perpendicular to EF. (Co-interier angles)

Now, APQEO is a pentagon.

Sum of all angles of pentagon = 540°

angleAPQ + anglePQE + angleQEO + angleEOA + angleOAF = 540°

90° + 90° + 140° + x + 125° = 540°

x = 540° - 445°

x = 95°

from the diagram

x + y = 360°

y = 360° - x

y = 360° - 95°

y = 265°

Answer 2

Heya...

• To make the APQEO a Pentagon...
√ Draw a line perpendicular to AB .
√ Now AB II EF .
√ PQ perpendicular to EF .

As we know :- Sum of all angles of Pentagon is = 540°

By putting values :-

Angle APQ + PQE + QEO + EOA + OAF
= 540°

90° + 90° + 140° + X + 125° = 540°

X = 540°- 445°

= 95 °

For the value of y

x + y = 360°

y = 360° - x

y = 360°-95°

= 265°

Thank you