Question

Please give me answer for this question .I study class 7. Quick quick!!!!!​

Answer 1

Answer:

a. 10°F fall in temperature.

Explanation:

°C > °F

Let initial temperature be x.

∴(x-10°C) = $[\frac{(x-10)X9}{5}]+32$ °F

=> $\frac{9x-90}{5} + 32$ °F

=> $\frac{9x}{5} - \frac{90}{5} +32$ °F

=> $\frac{9x}{5} - 18 + 32$ °F

=> $\frac{9x}{5} +14$ °F

=>$\frac{9x}{5} = -14$

∴ $(9x +70)$ °F

∴x-10=9x+70

=> -8x=70+10

=> -8x = 80

∴ x = -10

Hence, 10°C Fall in temperature is same as 10°F fall in temperature.

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