Question

please give me answer friends ​

Answer 1

Answer:

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Answer 2

Answer:

Given:

Uniform velocity of bus, u = 54 km/h.

Final velocity of bus, v = 72 km/h.

Time taken, t 10 seconds.

To Find:

Acceleration of bus is m/s ?

Distance covered by bus ?

Formula to be used:-

v = u + at

s = ut + 1/2at²

Solution:

First we need to change the uniform and final velocity into meter/second. To change multiply by 5/18.

Uniform velocity (u) = 54(5/18)

u = 15 m/s

Final velocity (v) = 72(5/18)

v = 20 m/s.

Now,put the values on formula

$\qquad\leadsto\quad \pmb {\mathfrak{ v = u + at}}$

$\qquad\leadsto\quad \pmb {\mathfrak{20 = 15 + a(10)}}$

$\qquad\leadsto\quad \pmb {\mathfrak{20 – 15 = 10\times a}}$

$\qquad\leadsto\quad \pmb {\mathfrak{5 = 10\times a}}$

$\qquad\leadsto\quad \pmb {\mathfrak{ \cancel{\dfrac{5}{10}} = a}}$

$\qquad\leadsto\quad \pmb {\mathfrak{a= 0.5 m/s²}}$

Acceleration of the bus is 0.5 m/s².

$\qquad\leadsto\quad \pmb {\mathfrak{s = ut + ½ at²}}$

$\qquad\leadsto\quad \pmb {\mathfrak{s = 15 \times 10 + ½ \times 0.5 \times (10)²}}$

$\qquad\leadsto\quad \pmb {\mathfrak{s = 150 + \dfrac{0.5}{2}\times 100}}$

$\qquad\leadsto\quad \pmb {\mathfrak{s = 150 + 0.5(50)}}$

$\qquad\leadsto\quad \pmb {\mathfrak{ s = 150 + 25}}$

$\qquad\leadsto\quad \pmb {\mathfrak{ s = 175 m}}$

Hence, the distance covered by bus is 175 m.