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Given:
Uniform velocity of bus, u = 54 km/h.
Final velocity of bus, v = 72 km/h.
Time taken, t 10 seconds.
To Find:
Acceleration of bus is m/s ?
Distance covered by bus ?
Formula to be used:-
v = u + at
s = ut + 1/2at²
Solution:
First we need to change the uniform and final velocity into meter/second. To change multiply by 5/18.
Uniform velocity (u) = 54(5/18)
u = 15 m/s
Final velocity (v) = 72(5/18)
v = 20 m/s.
Now,put the values on formula
Acceleration of the bus is 0.5 m/s².
Hence, the distance covered by bus is 175 m.
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