Physics, asked by saxenaamit8080, 7 months ago

please give me answer friends help me​

Attachments:

Answers

Answered by evilpunisher7
0

Answer:

broo its an questionn..

Explanation:

just apply the formula of 2 x (l+b)

Answered by Anonymous
4

dckbjbeee \tan( \tan( \sec( \time) ) ) ol}hjjqqppl\pi\pi\pi\pi\pi\pie \alpha  \gamma  \gamma \% \alpha \% \alpha \% \sin( \sin( \cot( \cot( \sin( \cot( \sin( \sin( \sin( \alpha  \infty  \infty  \alpha \% \alpha  \alpha e \alpha \pi \sin(e\%\%\%\%\%\% \binom{ \binom{\pi \alpha \pi \sin( \sec( \tan( \cos( \cos( \sin( \frac{ \frac{ \frac{ \frac{ { { { { \frac{ { { { {e \sin( \tan( \tan( \cos( \cos( \tan(?) ) ) ) ) )  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?} }^{?} }^{?} }^{?} }^{?}  \times \frac{?}{?}  \times \frac{?}{?} }{?}  \times \frac{?}{?} } \sin( \sec( \sec( \csc( \csc( \csc(\pi\pi\pi\pi\pi\pi\pi\pieeeeeee \gamma  \gamma  \gamma  \gamma  \gamma  \gamma  \gamma  \gamma  \tan( \tan( \tan( \tan( \tan( \tan( \cos( \cos( \cos( \cos( \cos( \sin( \sin( \sin( \sin( \sin( \alpha  ln( log( log_{ log_{ log_{ee\pi \csc( \csc( \csc( \sec( \sec( \cot( \cot( \tan( \cos( \sin( \alpha  log( log_{\% \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ \binom{ log( log( log( log( log( log( ln( ln( ln( \alpha  \csc( \sin( \sin( \sec(?) ) ) ) ) ) ) ) ) ) ) ) ) }{?} }{?} }{?} }{?} }{?} }{?} }{?} }{?} }{?} }{?} }{?} }(?) ) ) ) ) ) ) ) ) ) ) ) }(?) }(?) }(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ^{2} }^{?} }^{?} }^{?}  \times \frac{?}{?} }{?} }{?} }{?} }{?}  \times \frac{?}{?}  \times \frac{?}{?} ) ) ) ) ) ) }{?} }{?} ) ) ) ) ) ) ) ) ) )

Similar questions