Question

please give me answer iwill mark brainliest​

Answer 1

Perimeter of ABE = $(3\frac{1}{3} + 2\frac{1}{5} + 4\frac{2}{3} )$ cm = $\frac{153}{15}$ cm

Since, BCDE is a rectangle then its perimeter is

$2 (1\frac{2}{3} + 2\frac{1}{5})$ cm = 2× $\frac{58}{15}$ = $\frac{116}{15}$cm

you can see that ABE's perimeter is greater by

$\frac{153-116}{15} cm = \frac{37}{15}cm$