please give me answer of 4th and 5th please
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iv) ∆ xyz is right angle triangle were xz is hypotenuse
so , by Pythagoras theorem
xz² = xy² +yz²
xz² = (12)² +(5)²
xy² = 144+25
xy² = 169
xy = 13
now in triangle ypx were at angle p is right angle
so by Pythagoras theorem
yx² = pz²+ yp²
(12)² = (6.5)²+yp² (given yp is a median)
yp² = 144 - 42.25
yp² = 102.25
yp = 5√5 approx
i hope it will help you
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