Question

Please give me answer of following fast and l will mark you as Brainliest ​

Answer 1

Answer:

ÑØW_PLZZZZZZZZZZZZZZZZ_ MÀRK_MY_ÀNSWÈR_THÉ_BRAÍÑLIÉST_AÑSWÉR

Answer 2

Answer:

$\large\underline{ \underline{ \red {your \: \: \: answe }}} \\ 1) {4x}^{3} + {8x}^{2} - x - 2 \\2)( {5x}^{2} + {y}^{2} )( {5x}^{2} - {y}^{2} ) \\ 3) {5}^{3} \times {2}^{6} \\ 4)x = - 1 \\ 5) \frac{ {x}^{2} + 1 }{ {x}^{2} }$

Step-by-step explanation:

$1) \bf\ \mapsto \bigstar(2x + 1)(x + 2)(2x - 1) \bigstar \\ \\\bf\ \implies(2x + 1)(2x - 1)](x + 2)\\ \\ \bf\ \implies [ ({2x})^{2} - {1}^{2}](x + 2) \: \: \: \: \: [\therefore (x + y)(x - y) = {x}^{2} - {y}^{2}] \\ \\ \bf\ \implies( {4x}^{2} - 1)(x + 2) \\ \\ \bf\underline { \implies {4x}^{3} + {8x}^{2} - x - 2 }\\ \\ \\ 2) \bigstar \bf\ {25x}^{4} - {y}^{4} \bigstar \\ \\ \bf\ \leadsto { ({5x}^{2} )}^{2} - ({ {y}^{2}) }^{2} \: \: \: \: \: [\therefore {x}^{2} - {y}^{2} = (x + y)(x - y) ] \\ \\ \bf\red{ \leadsto ( {5x}^{2} - {y}^{2})( {5x}^{2} + {y}^{2} ) } \\ \\ 3)\bf\ \bigstar \frac{ {5}^{5} \times {3}^{ - 5} }{125 \times {6}^{ - 5} \times {10}^{ - 1} } \bigstar \\ \\ \bf\ \hookrightarrow \frac{ {5}^{5} \times \frac{1}{ {3}^{5} } }{ {5}^{3} \times \frac{1}{ {6}^{5} } \times \frac{1}{10} } \\ \\ \bf\ \hookrightarrow \frac{ \frac{ {5}^{5} }{ {3}^{5} } }{ \frac{ {5}^{3} }{ {6}^{5} \times 10 } } \\ \\ \bf\ \hookrightarrow \frac{ {5}^{5} }{ {3}^{5} } \times \frac{ {6}^{5} \times 10 }{ {5}^{3} } \\ \\ \bf\ \hookrightarrow \frac{ {5}^{5} \times ( {2}^{5} \times {3}^{5} ) \times (2 \times 5) }{ {3}^{5} \times {5}^{3} } \\ \\ \bf\ \hookrightarrow \frac{ {5}^{5} \times 5 \times {2}^{5} \times 2 }{ {5}^{3} } \\ \\ \bf\ \hookrightarrow \frac{ {5}^{5 + 1} \times {2}^{5 + 1} }{ {5}^{3} } \\ \\ \bf\ \hookrightarrow \frac{ {5}^{6} \times {2}^{6} }{ {5}^{3} } \\ \\ \bf\ \hookrightarrow {5}^{6 - 3} \times {2}^{6} \\ \\ \bf\boxed{ \hookrightarrow {5}^{3} \times {2}^{6}} \\ \\ 4)\bigstar \bf\ \: \frac{ ({ \frac{5}{7}) }^{ - x} }{ ({ \frac{5}{7}) }^{ - 4} } = (\frac{5}{7})^{ 5} \bigstar \\ \\ \bf\ \leadsto { \frac{5}{7} }^{ - x - ( - 4)} = { \frac{5}{7} }^{5} \\ \\ \bf\ \leadsto - x - ( - 4) = 5 \\ \\ \bf\ \leadsto - x + 4 = 5 \\ \\ \bf\ \leadsto - x = 5 - 4 \\ \\ \bf\ \leadsto - x = 1 \\ \\ \bf\ \underline{ x = - 1} \\ \\ \bf\ \bigstar {x}^{2} + \frac{1}{ {x}^{2} } \bigstar \\ \\ \bf\ \boxed{ \frac{ {x}^{4} + 1}{ {x}^{2} } }$

$\large\boxed{ \fcolorbox{lime}{orange}{hope \: it \: help \: you}}$