Question

please give me answer of maths question 1​

Answer 1

Step-by-step explanation:

FIRST TAKE A COMPASS WITH PENCIL .

NOW TAKE THE LENGTH OF COMPASS 8 CM

AND DRAW A LINE.

NOW FROM THE CENTER OF LINE THAT IS 4CM DRAW A LINE PERPENDICULAR TO IT WITH LENGTH 4 CM

THE LENGTH OF EQUAL SIDES WILL BE

4^2+4^2=S^2

32=H^2

H=_/32

NOW CHANGE _/32 IN DECIMAL FORM

that is 5.6568 (approx.)

now put compass on one end of line or base with the length 5.65 and make an arc on the other end of the altitude

now take another end of line (8cm)now cut another arc on the same end of altitude (4cm)with length 5.65.

and join the points of the altitudes with both ends and you will get the answer!

Answer 2

Answer:

Steps of construction:

1. Draw a base BC of length 8 cm.

2. Draw the perpendicular bisector of BC and name it PQ. Let it intersect BC in M.

3. From M, mark an arc A at a distance of 4 cm on PQ.

4. Join B−A and C−B. △ABC is the first isosceles triangle.

5. Extend BC and BA. Place the pointed end of the compass at C and mark an arc of radius CM on the opposite side of M on the extended segment BC. Mark the point as D (Since CM is half of BC, BD will be BC+0.5BC=1.5BC)

6. From D, draw a line parallel to AC and let it intersect the extended segment AB at E.

△EBD is the required similar triangle.

solution

diagram in the attachment~